A carpenter must cut a piece of wood so that it fits tightly into position. The carpenter cuts 3/16 of an inch off the wood so that it measures 4 1/2 inches. What was the size of the original piece of wood?

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Answer:

The size of the original piece of the wood will be = 24 inches.

Step-by-step explanation:

Let the original sizeof the wood be = x inches.

Now, according to the question the carpenter cuts 3/16 of an inch off the wood so that it measures 4 1/2 inches that is [tex]\frac{9}{2}[/tex]inches.

Thus, [tex]\frac{3}{16}x=\frac{9}{2}[/tex]

⇒[tex]x=\frac{9}{2}{\times}\frac{16}{3}[/tex]

⇒[tex]x=24[/tex]inches

Thus, the size of the original piece of the wood will be = 24 inches.

Answer:

Original length of the wood is 24 inches.

Step-by-step explanation:

Let the original length of the wood = x inches.

It is given that, [tex]\frac{3}{16}[/tex] inches of the wood is cut, so that it measures [tex]4\frac{1}{2}[/tex] i.e. [tex]\frac{9}{2}[/tex]inches

So, we have the equation,

[tex]\frac{3}{16}x=\frac{9}{2}[/tex]

i.e. [tex]x=\frac{9\times 16}{2\times 3}[/tex]

i.e. [tex]x=\frac{144}{6}[/tex]

i.e. x = 24 inches

Thus, the original length of the wood is 24 inches.