what is the inverse of the given relation

y=7x^2-3

a. y= +/- sqrt x+3/7
b. x= sqrt y+3/7
c. y^2 = x+3/7
d. y= +/- sqrt x-3/7

Respuesta :

Answer:

A


Step-by-step explanation:

To find the inverse, we will follow the steps below:

1. Interchange x and y

2. solve for new y


Hence,

[tex]y=7x^2 - 3\\x=7y^2-3\\x+3=7y^2\\\frac{x+3}{7}=y^2\\+-\sqrt{\frac{x+3}{7}} =y[/tex]


Answer is  [tex]y=+-\sqrt{\frac{x+3}{7}}[/tex]

Answer choice A is right.

Answer:

y= +/- sqrt x+3/7