As we know from kepler's law that
[tex]\frac{T_1^2}{T_2^2} = \frac{r_1^3}{r_2^3}[/tex]
here we know that for earth we have time period T = 1 year and its average distance from Sun is 1 AU
so here from above equation we have
[tex]\frac{1^2}{309.1^2} = \frac{1^3}{r^3}[/tex]
from above equation we have
[tex]r = 45.7 AU[/tex]
as we also know that
[tex]1 AU = 1.5 \times 10^{11} km[/tex]
so average distance will be
[tex]r = 6.86 \times 10^{12} km[/tex]
