Given f(x)=3x2+4x and g(x)=2x2−x+1 .

What is (f+g)(x) ?

​ x^2+5x−1 ​

−x^2−5x−1

5x^2+3x+1

​ 6x^2−4x+1 ​

Respuesta :

3z^2 + 4x + 2x^2 - x + 1

5x^2 + 3x + 1: the answer is c

The value of (f+g)(x), Given f(x)=3x²+4x and g(x)=2x²−x+1  is 5x²+3x+1

Note that, (f+g)(x) is can also be expressed as f(x)+g(x).

⇒ From the expression,

  • f(x) = 3x²+4x
  • g(x) = 2x²-x+1

⇒ Then,

  • (f+g)(x) = (3x²+4x)+(2x²-x+1)

⇒ Collecting like terms

  • (f+g)(x) = 3x²+2x²+4x-x+1
  • (f+g)(x) = 5x²+3x+1

Hence, The right answer is 5x²+3x+1

Therefore, The value of (f+g)(x), Given f(x)=3x²+4x and g(x)=2x²−x+1  is 5x²+3x+1

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