Answer:
b. 40 yd²
Step-by-step explanation:
We have the square and the right triangle.
The formula of an area of a square:
[tex]A_{\boxed{}}=a^2[/tex]
a - length of side
The formula of an area of a right triangle:
[tex]A_\triangle=\dfrac{ab}{2}[/tex]
a,b - legs
We have:
SQUARE:
a = 4 yd
[tex]A_{\boxed{}}=4^2=16\ yd^2[/tex]
RIGHT TRIANGLE:
a = 6 yd, b = 4 yd + 4 yd = 8 yd
[tex]A_\triangle=\dfrac{(6)(8)}{2}=(3)(8)=24\ yd^2[/tex]
The area of the figure:
[tex]A=A_{\boxed{}}+A_\triangle\\\\A=16\ yd^2+24\ yd^2=40\ yd^2[/tex]
