Respuesta :

SaniShahbaz

Answer:

Option B is correct

Step-by-step explanation:

2x² - 6x + 3 = 0

Using Quadratic formula:

x = [tex]\frac{-b+-\sqrt{b^{2}-4ac}}{2a}[/tex]

a = 2, b = -6, c = 3

x = [tex]\frac-(-6)+-{\sqrt{(-6)^{2}-4(2)(3)}}{2(2)}[/tex]

x = [tex]\frac{-(-6)+-\sqrt{(-6)^{2}-4(2)(3)}}{2(2)}\\[/tex]

[tex]=\frac{6+-\sqrt{36-24}}{4}\\\\=\frac{6+-\sqrt{12}}{4}\\\\=\frac{6+-3.46}{4}\\\\[/tex]

[tex]=\frac{6+3.46}{4}[/tex]

x = 2.37  


[tex]=\frac{6-3.46}{4}[/tex]

 x = 0.63      

   


zainebamir540

Answer:

Choice C is correct answer.

Step-by-step explanation:

Given equation is :

2x²-6x+3= 0

ax²+bx+c = 0 is general quadratic equation.

x = (-b±√b²-4ac) / 2a is quadratic formula to solve general quadratic equation.

comparing given equation with general quadratic equation,we get

a = 2 , b = -6 and c = 3

putting above values in quadratic formula: we get

x = (-(-6)±√(-6)²-4(2)(3)) / 2(2)

x = (6±√36-24) / 4

x = (6±√12) / 4

x = (6±2√3) / 4

x = 2(3±√3) / 4

x = 3±√3 / 2

x = 3±1.73 / 2

x = (3+1.73) / 2 or x = (3-1.73) / 2

x = 4.73 / 2 or x = 1.27 / 2

x =  2.37  or x = .63 is solution of 2x²-6x+3 = 0.



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