Respuesta :
Answer: The answer is 20 inches.
Step-by-step explanation: As given in the question and shown in the attached figure, Keyley drew the rectangle 'R' and square 'S' with equal areas.
Also, the length of Keyley's rectangle 'R' = 8 inches. Let the breadth be 'b' inches. Again, let 'l' be the length of a side of square 'S'.
Then, we must have
[tex]8\times b=\ell^2.[/tex]
Now, the only possible value of b is 2, so that
[tex]\ell^2=16\\\\\Rightarrow \ell=4.[/tex]
Thus, the breadth of 'R' is b = 2 inches and side of 'S' = 4 inches.
Therefore, perimeter of Keyley's rectangle 'R' is given by
[tex]p=8+2+8+2=20~\textup{inches}.[/tex]
Thus, the answer is 20 inches.
Answer:
perimeter of Keyley's rectangle is 20 inches.
Step-by-step explanation:
Given : Keyle drew the rectangle 'R' and square 'S' with equal areas.The length of Kelsey's rectangle is 8 inches.
Find: What is the perimeter in inches of Kelsey's rectangle.
Solution:
Length of Keyley's rectangle = 8 inches.
Let the breadth be 'b' inches. Again, let 'l' be the length of a side of square .
Area of rectangle = area of square
length * width = length *length
8 * width = [tex]l^{2}[/tex]
Now, the only possible value of b is 2, so that
Area of square ( [tex]l^{2}[/tex] )= 16
Plugging the values of [tex]l^{2}[/tex] = 16 in 8 * width = [tex]l^{2}[/tex]
8 * width =16
Width = 2
Perimeter of rectangle = 2 ( length + width)
Perimeter = 2 ( 8 + 2 )
Perimeter = 20 inches
Therefore, perimeter of Keyley's rectangle is 20 inches.
