[tex]\bf \qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &330\\ r=rate\to 25.5\%\to \frac{25.5}{100}\dotfill &0.255\\ t=\textit{elapsed time}\dotfill &5\\ \end{cases} \\\\\\ A=330(1-0.255)^5\implies A=330(0.745)^5 \\\\\\ A\approx 75.7347687\implies \stackrel{\textit{rounded up}}{A=75.7}[/tex]
