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A 2.40 L volume of air has a pressure of 101.7 kPa. If initially the pressure of the air was 101.01 kPa, what was the initial volume of air? Assume all other properties remain constant.

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Answer:

2.42 L  

Step-by-step explanation:

Since all other properties constant, we can use Boyle’s Law.

p₁V₁ = p₂V₂    Divide each side by p₁

  V₁ = V₂ × p₂/p₁

Data:

p₁ = 101.01 kPa; V₁ = ?

p₂ = 101.7   kPa; V₂ = 2.40 L

Calculations:

V₁ = 2.40 × 101.7/101.01

V₁ = 2.42 L

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