Answer: (D) 7a⁴
Step-by-step explanation:
[tex]\sqrt{49a^8}[/tex]
[tex]=\sqrt{49} \ \cdot \sqrt{a^8}[/tex]
[tex]=\sqrt{7\cdot 7} \ \cdot \sqrt{a\cdot a\cdot a\cdot a\cdot a\cdot a\cdot a\cdot a}[/tex]
Two on the inside of the radical (square root) symbol makes One on the outside. Simplify by looking for pairs.
[tex]=\sqrt{\underline{7\cdot 7}} \ \cdot \sqrt{\underline{a\cdot a}\cdot \underline{a\cdot a}\cdot \underline{a\cdot a}\cdot \underline{a\cdot a}}[/tex]
= 7 · a · a · a · a
= 7a⁴
