Respuesta :

gmany

[tex]3rs-5cr-15cs+25c^2=r(3s-5c)-5c(3s-5c)\\\\=(3s-5c)(r-5c)\\\\Answer:\ \boxed{3rs-5cr-15cs+25c^2=(3s-5c)(r-5c)}[/tex]

MileenaKitana
Your answer would be 3rs-5cr-15cs+50c

A trick that I have learned, but does not apply to all equations, (some don’t work with this) is to multiply +25c by 2 to get =50c.