Answer:
First question answer: The limit is 69
Second question answer: The limit is 5
Step-by-step explanation:
For the first limit, plug in [tex]x=8[/tex] in the expression [tex](9x-3)[/tex], that's the answer for linear equations and limits.
So we have:
[tex]9x-3\\9(8)-3\\72-3\\69[/tex]
The answer is 69
For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value [tex]x=1[/tex] into the simplified expression to get the correct answer. Shown below:
[tex]\frac{x^2+8x-9}{x^2-1}\\\frac{(x+9)(x-1)}{(x-1)(x+1)}\\\frac{x+9}{x+1}[/tex]
Now putting 1 in [tex]x[/tex] gives us the limit:
[tex]\frac{x+9}{x+1}\\\frac{1+9}{1+1}=\frac{10}{2}=5[/tex]
So the answer is 5
