Respuesta :

chloe8668
(-2-2i)(-4+6i)
=8-12i+8i-12i^2
=8-4i-12i^2
=4(2-i-3i^2)
=4((i-1)(3i+2))
=4(i-1)(3i+2)
facundo3141592

Answer: (-2-2i)(-4+6i) = 20 - 4i

Step-by-step explanation:

We have the expression:

(-2 - 2i)*(-4 + 6i)

the rule we need to know here is that i*i = -1

now, the first step is distribute the parentheses.

(-2 - 2i)*(-4 + 6i) = -2*-4 -2*6i - 2i*-4 - 2i*6i = 8 -12i + 8i -12*(i*i)

= 8 + (8 - 12)i +12 = 20 - 4i

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