Respuesta :
Answer:
(a)
[tex]40=1,2,4,5,8,10,20,40[/tex]
(b)
factor=5 can only hold it
(c)
Only one arrangement is possible
(d)
we can put 5 cans into all 8 shelves
(e)
[tex]40=8\times 5[/tex]
Step-by-step explanation:
We are given
an empty kitchen cabinet has 8 shelves
and each shelf can hold no more than 30 cans you want to arrange 40 cans in the kitchen cabinet
so that the same number of cans is on each shelf that you use
(a)
we can find all possible factors of 40
[tex]40=1,2,4,5,8,10,20,40[/tex]
(b)
Since, an empty kitchen cabinet has 8 shelves
so, one of factor of 40 must be 8
so,
[tex]40=8\times 5[/tex]
So, factor=5 can only hold it
(c)
Only one arrangement is possible
because there is only one such possible factor
[tex]40=8\times 5[/tex]
(d)
Since, we got
[tex]40=8\times 5[/tex]
So, we can put 5 cans into all 8 shelves
(e)
Since, there are 8 shelves
and we can put 5 cans on each shelves
so, possible arrangement is
[tex]40=8\times 5[/tex]
Answer:
(a) 40 = 1 x 40, 2 x 20, 4 x 10, or 5 x 8. Factors of 40: 1, 2, 4, 5, 8, 10, 20, 40
(b) Factors: 5, 8, 10, 20
(c) 4, that is, the quantity of factors in (b)
(d) 5 cans in 8 shelves, 8 cans in 5 shelves, 10 cans in 4 shelves, 20 cans in 2 shelves.
