Answer: Option B: 1.3×10⁵ W
Explanation:
[tex]Power = \frac{Work \hspace{1mm} done}{Time}[/tex]
[tex]P=\frac{W}{t}[/tex]
Work Done, [tex]W= F.s[/tex]
Where s is displacement in the direction of force and F is force.
[tex]\Rightarrow P = \frac{F.s}{t} =F \times \frac{s}{t}=F.v[/tex]
where, v is the velocity.
It is given that, F = 5.75 × 10³N
v = 22 m/s
P = 5.75 × 10³N×22 m/s = 126.5 × 10³ W ≈1.3×10⁵W
Thus, the correct option is B
