write an equation in standard form for a line that is (a) parallel (b) to the line with an equation of y=3x-5 that passes through the point (8,5)

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Answer:

The parallel line would be y = 3x - 19

Step-by-step explanation:

In order to find the equation of this line, we first have to note that parallel lines have same slopes. Therefore, since the original line has a slope of 3, we know the new line will have a slope of 3. Now we can use that information along with the given point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 5 = 3(x - 8)

y - 5 = 3x - 24

y = 3x - 19

The equation of the line in standard form is 3x - y = 19

The equation of a line in point slope form is expressed as;

y - y0 = m(x - x0)

  • m is the slope of the line
  • ()x0, y0) is any point on the line

Given the equation y = 3x - 5, get the slope;

mx = 3x

m = 3

Substitute  m = 3 and the point (8, 5) into the formula to have:

y - 5 = 3(x - 8)

y - 5 = 3x - 24

3x - y = 19

Hence the equation of the line in standard form is 3x - y = 19

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