Given:
Initial volume of water V1 = 6.00 ml
Initial concentration of NaCl M1 = 0.750 M
Volume of water added = 4.00 ml
To determine:
The final concentration M2 of NaCl
Explanation:
The final volume V2 = 6.00 + 4.00 = 10.0 ml
Use the relation:
M1V1 = M2V2
M2 = M1V1/V2 = 0.750*6.00/10.0 = 0.450 M
Ans: The concentration fo diluted NaCl = 0.450 M
