[tex]\bf \cfrac{5}{\frac{1}{6}+\frac{1}{x+1}}\implies \cfrac{5}{\stackrel{\textit{our LCD here will just be 6(x+1)}}{\frac{(x+1)1~~+~~(6)1}{6(x+1)}}}\implies \cfrac{5}{\frac{x+1~~+~~6}{6(x+1)}} \\\\\\ \cfrac{\frac{5}{1}}{~~\frac{x+7}{6(x+1)}~~}\implies \cfrac{5}{1}\cdot \cfrac{6(x+1)}{x+7}\implies \cfrac{30(x+1)}{x+7}[/tex]
now, we could distribute the 30 up there, but simplification wise, it won't matter.