Answer:
B) [tex]\frac{\sqrt{3} + \sqrt{6} }{8}[/tex]
Step-by-step explanation:
The given expression is [tex]\frac{(3 + \sqrt{18} }{4\sqrt{12} }[/tex]
We should not have the radical sign in the denominator. To get rid of the radical number, we multiply both the numerator and the denominator by 4√12.
= [tex]\frac{(3 + \sqrt{18} }{4\sqrt{12} } * \frac{4\sqrt{12} }{4\sqrt{12} }[/tex]
= [tex]\frac{12\sqrt{12} + 4\sqrt{18} \sqrt{12} }{16*12}[/tex]
= [tex]\frac{24\sqrt{3} + 24\sqrt{6} }{192}[/tex]
= [tex]\frac{24(\sqrt{3}+\sqrt{6} ) }{192} \\[/tex]
Now we can cancel out 24/192, which is 1/8
= [tex]\frac{\sqrt{3}+\sqrt{6} }{8}[/tex]
Answer is B.
Thank you.
