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A researcher studying the nutritional value of a new candy places a 5.00-gram sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.77 °C. If the heat capacity of the calorimeter is 47.10 kJ·K–1, how many nutritional Calories are there per gram of the candy?

Respuesta :

Answer: 6236.48 cal/gram

Explanation:[tex]Q= c\times \Delta T[/tex]

Q= heat released

c = heat capacity of substance [tex]=47.10 kJK^{-1}=47100 JouleK^{-1}= 11.25kcalK^{-1}[/tex]      

(1Joule=0.00024kCal)   (1kcal=1000cal)

[tex]\Delta T[/tex]=Change in temperature= 2.77C= 2.77K

[tex]Q= 11257.17calK^{-1}\times 2.77K[/tex]

[tex]Q= 31182.4cal[/tex]

Now heat released per gram of the candy=[tex]\frac{31182.4cal}{5.00g}[/tex]

[tex]=6236.48cal/gram[/tex]




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