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Write an equation in point-slope form for the line that has a slope of 56 and contains the point (−8,−4).


x−8=56(y−4)

y−4=56(x−8)

y+8=56(x+4)

y+4=56(x+8)

Respuesta :

gmany

The point-slope form:

[tex]y-y_1=m(x-x_1)[/tex]

We have m = 56 and the point (-8, -4). Substitute:

[tex]y-(-4)=56(x-(-8))\\\\\boxed{y+4=56(x+8)}[/tex]

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