Answer:
10.6 units
Step-by-step explanation:
First of all, let's find the magnitude of the first vector, which is given by the resultant of its two components:
[tex]R=\sqrt{32^2+28^2}=42.5[/tex] units
The second vector has a length which is 1/4 of the length of the first vector, so it is
[tex]R'=\frac{1}{4}R=\frac{1}{4}(42.5)=10.6[/tex] units
