Respuesta :

Answer:

OMG IN K12 WORKING ON THIS RN I THINK I GET IT ITS BE

Step-by-step explanation: YOU HAVE TO DO AS THE EQAUTION SAYS


    x^2 - 4               x^3 - x^2 - 6x

------------------- /  -------------------------------

 x^3 + 7x^2            x^2 + 4x - 21    


  (x+2)(x - 2)             x(x^2 - x - 6)

= ------------------- /  ----------------------

  x^2(x + 7)               (x + 7)(x - 3)  


  (x+2)(x - 2)             x(x - 3)(x + 2)

= ------------------- /  ----------------------

  x^2(x + 7)               (x + 7)(x - 3)  


  (x+2)(x - 2)             (x + 7)(x - 3)

= ------------------- *  ----------------------

  x^2(x + 7)              x(x - 3)(x + 2)


     x - 2            

= -------------

      x^3      

Answer is C