Answer:
The correct option is A) Multiply [tex]\frac{6y+8}{3y}(\frac{5y}{5y})[/tex] and [tex]\frac{2y}{5y^2}(\frac{3}{3})[/tex].
Step-by-step explanation:
Consider the provided expression.
Subtract [tex]\frac{6y+8}{3y}[/tex] from [tex]\frac{2y}{5y^2}[/tex]
It is given that LCD of the expression is 15y².
Now observe the denominator of each expression.
The expression [tex]\frac{6y+8}{3y}[/tex] has denominator 3y.
In order to make denominator 15y² multiply 3y with 5y.
[tex]3y\times{5y}=15y^2[/tex]
The expression [tex]\frac{2y}{5y^2}[/tex] has denominator 5y².
In order to make denominator 15y² in second expression, multiply 5y² with 3.
[tex]5y^2\times{3}=15y^2[/tex]
Thus, the next step is:
Multiply [tex]\frac{6y+8}{3y}(\frac{5y}{5y})[/tex] and [tex]\frac{2y}{5y^2}(\frac{3}{3})[/tex].
Therefore, the correct option is A) Multiply [tex]\frac{6y+8}{3y}(\frac{5y}{5y})[/tex] and [tex]\frac{2y}{5y^2}(\frac{3}{3})[/tex].
