contestada

A cyclist accelerates from 0 m/s to 8 m/s in 3 seconds. What is his acceleration? Is this acceleration higher than that of a car which accelerates from 0 to 30 m/s in 8 seconds

Respuesta :

The average acceleration of an object is calculated as the final speed minus the initial speed divided by the elapsed time.

So:

[tex]a = \frac{V_f-V_0}{T_2-T_1}[/tex]

Where

[tex]V_f[/tex]= final speed

[tex]V_0[/tex] = initial speed

[tex]T_2-T_1[/tex] = elapsed time.

Thus:

The acceleration of the cyclist is:

[tex]a = \frac{8-0}{3}[/tex]

a = 2.667[tex]m / s ^ 2[/tex]

The acceleration of the car is:

[tex]a = \frac{30-0}{8}[/tex]

a = 3.75 [tex]m/s^2[/tex]

The average acceleration of the car is higher than the average acceleration of the cyclist.