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What is the completely factored form of f(x)=x3−7x2+2x+4?




f(x)=(x−1)(x−(3+52−−√))(x−(3−52−−√))

f(x)=(x+1)(x−(3+13−−√))(x−(3−13−−√))

f(x)=(x+1)(x−(3+52−−√))(x−(3−52−−√))

f(x)=(x−1)(x−(3+13−−√))(x−(3−13−−√))

Respuesta :

sqdancefan

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Answer:

  (d)  f(x) = (x -1)(x -3+√13)(x -3-√13)

Step-by-step explanation:

A graphing calculator shows that factoring out (x -1) gives ...

  f(x) = (x -1)((x -3)^2 -13)

The quadratic factor will have roots ...

  x = 3±√13

so the remaining factors are ...

  f(x) = (x -1)(x -3+√13)(x -3-√13)

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A root of p means (x -p) is a factor.

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