Respuesta :

carlosego

For this case we have:


By trigonometric property we have:


[tex]Cosine(\alpha)=\frac{AdjacentLeg}{Hypotenuse}[/tex]

Where:


[tex]Adjacent Leg = 12\\Hypotenuse = 13\\\alpha= x[/tex]

Substituting:


[tex]Cosine(x)=\frac{12}{13}[/tex]

Clearing x we have:


[tex]x =Cosine^{-1}(\frac{12}{13})[/tex]

Thus, the equation is: [tex]x =Cosine^{-1}(\frac{12}{13})[/tex]

Answer:


[tex]x =Cosine^{-1}(\frac{12}{13})[/tex]


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