man101
man101
28-10-2018
Mathematics
contestada
3 exponet 8×4+9÷1×56+57
Respuesta :
SimplySnowy
SimplySnowy
28-10-2018
You would use PEMDAS
But since any number divided by 1 is the number by which it is divided by then you can eliminate that. Now your problem looks like this:
8✖️4➕9✖️56➕57
Since there are no parentheses or exponents then you would multiply.
8✖️4= 32
32➕9✖️56➕57
Then multiply the other multiplication problem.
9✖️56= 504
32➕504➕57
Now you can add all of the numbers together
32➕504=536
536➕57=593
Your answer is 593
Hope this helps! :3
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