Respuesta :

distribute
remember the -1 infront of the second set of partnhasees
a(b+c)=ab+ac
2(3/5x+3)=6/5x+6
-1(2/3x-1)=-2/3x+1
we now have
6/5x+6-2/3x+1
gropu like terms
6/5x-2/3x+6+1
add like terms
6/5x-2/3x+7
make bottom numbers same
6/5x times 3/3=18/15x
2/3x times 5/5=10/15x
18/15x-10/15x+7
8/15x+7
equivilent is 8/15x+7
To solve this, we must multiply what's outside of the parentheses by what is inside. 
For the first parenthetic set, we can see that we are multiplying the values by 2, so we do it this way:

[tex]2( \frac{3}{5}x + 3) = (2 * \frac{3}{5}x) + (2 * 3) = \frac{6}{5}x + 6[/tex]

For the second part of the expression, we don't see any value, but we understand that there is a negative 1 that we don't see, because of the minus sign between the two parenthetic sets.
So we end up with this:

[tex]- (\frac{2}{3}x - 1) = (-1 * \frac{2}{3}x) + (-1 * -1) = (\frac{-2}{3}x + 1)[/tex]

So, without parentheses, the expression looks like this:

[tex]\frac{6}{5}x + 6 + \frac{-2}{3}x + 1[/tex]

Which could be further reduced to

[tex] \frac{8}{15}x + 7 [/tex]

Hope that helped! =)