Answer:
The function [tex]g(x) = x-1[/tex]
Step-by-step explanation:
Here [tex]f(x) = x-2[/tex]
Let [tex]y=x-2[/tex]
Solving for x we get
[tex]x=y+2[/tex] ....(1)
We are also given that
[tex]g(f(x)) = x-3[/tex]
So we replace [tex]f(x) \ by \ y[/tex]
We get
[tex]g(y) = x-3[/tex]
But [tex]x=y+2 \ from \ (1)[/tex]
We have
[tex]g(y) = y+2-3[/tex]
[tex]g(y)=y-1[/tex]
or
[tex]g(x)=x-1[/tex]