Respuesta :
Answer:
[tex]24x^6[/tex] and [tex]y^{15}[/tex]
Step-by-step explanation:
We know the formula for finding the area of a rectangle:
Area of a rectangle = l x w
where l = length; and
w = width
Given an expression [tex]24x^{6} y^{15}[/tex]for the area of a rectangle, we can divide it into two parts:
[tex]24x^6[/tex] and [tex]y^{15}[/tex]
Therefore, we can determine the length and width of the rectangle to be [tex]24x^6[/tex] and [tex]y^{15}[/tex] respectively.
The length of the rectangle with area [tex]24{x^6}{y^{15}}[/tex] is [tex]\boxed{24{x^6}}[/tex] and the width of the rectangle is [tex]\boxed{{y^{15}}}.[/tex]
Further Explanation:
The formula of area of rectangle can be expressed as follows,
[tex]\boxed{Area=\left( l \right)\times\left( w \right)}[/tex]
The formula of perimeter of the rectangle can be expressed as follows,
[tex]\boxed{{\text{Perimeter}}=2\left( {l + w}\right)}[/tex]
Here, “l” represents the length of the rectangle and “w” represents the width of the rectangle.
Explanation:
The given area of the rectangle is [tex]24{x^6}{y^{15}}.[/tex]
Compare the formula of the rectangle [tex]Area = \left( l \right) \times\left( w \right)[/tex] with the given area of the rectangle to obtain the dimensions of the rectangle.
By comparing the length of the rectangle is [tex]24{x^6}}[/tex] and the width of rectangle is [tex]{y^{15}}.[/tex]
The length of the rectangle with area [tex]24{x^6}{y^{15}}[/tex] is [tex]\boxed{24{x^6}}[/tex] and the width of the rectangle is [tex]\boxed{{y^{15}}}.[/tex]
Learn more:
1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
2. Learn more about equation of circle brainly.com/question/1506955.
3. Learn more about range and domain of the function https://brainly.com/question/3412497
Answer details:
Grade: Middle School
Subject: Mathematics
Chapter: Mensuration
Keywords: rectangle, length, width, breadth, area of rectangle, circumference of rectangle, dimensions of rectangle, expression, equation, square.
