a man walked back and forth in a straight line. if he travels from point A to point B, then turns around and stops at point C, what is his total displacement after 2 minutes?
A. 150
B. 350
C. 100
D.50

a man walked back and forth in a straight line if he travels from point A to point B then turns around and stops at point C what is his total displacement after class=

Respuesta :

Answer : The total displacement after 2 minutes is 50 m.

Solution :

Displacement : It is defined as the change in the position of an object. It is a vector quantity that means it has direction as well as magnitude.

In mathematical term, it is defined as,

[tex]Displacement=\text{ change in position of an object}=\Delta x=x_{final}-x_{initial}[/tex]

By using this formula, we get the total displacement after 2 minutes.

Initial position, A = 0 m

Final position, C = 50 m

Now put the given values in above formula, we get

[tex]Displacement=x_{final}-x_{initial}=50m-0m=50m[/tex]

Therefore, the total displacement after 2 minutes is 50 m.


The answer is D.50

Hope i helped