Respuesta :

altavistard

Start with y = 2x.  Subst. a for x and a+sqrt(3) for y:

a+sqrt(3) = 2a

Subtracting a from both sides:  sqrt(3) = a

kudzordzifrancis
If the point
[tex](a \: \: a \sqrt{3} )[/tex]
lies on
[tex]y = 2x[/tex]
then it must satisfy it.

That is

[tex]a + \sqrt{3} = 2(a)[/tex]
[tex] \rightarrow \: a + \sqrt{3} = 2a[/tex]


Grouping like terms we have,

[tex] \sqrt{3} = 2a - a[/tex]
[tex] \therefore \: a = \sqrt{3} [/tex]

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