I need help writing an equation of a graph in slope-intercept form & standard form. Plz (:

y = - [tex]\frac{2}{3}[/tex] x + 2 abd 2x + 3y = 6
The equation of a line in ' slope- intercept form ' is
y = mx + c → ( m is slope and c is the y- intercept)
The graph here slopes downwards from left to right thus slope is negative
m = - [tex]\frac{2}{3}[/tex] and c = 2
y = - [tex]\frac{2}{3}[/tex] x + 2 in slope- intercept form
the equation of a line in standard form is Ax + By = C
where A is a positive integer and B, C are integers
multiply all terms in the slope- intercept equation by 3
3y = - 2x + 6 → add 2x to both sides
2x + 3y = 6 in standard form