Respuesta :
we are given
initial velocity is +1.0 m/s
so, [tex]u=1.0m/s[/tex]
Let's assume final velocity as v
uniformly accelerating at +4.9m/s^2
so, [tex]a=4.9m/s^2[/tex]
time is 4 sec
so, t=4 s
now, we can use formula
[tex]a=\frac{v-u}{t}[/tex]
we can plug values
[tex]4.9=\frac{v-1}{4}[/tex]
[tex]4.9*4=4*\frac{v-1}{4}[/tex]
[tex]4.9*4=v-1[/tex]
[tex]19.6=v-1[/tex]
[tex]v=20.6m/s[/tex]...............Answer
Answer:
So velocity of ball after 4 sec will be 20.6 m/sec
Step-by-step explanation:
We have given initial velocity of the ball u = 1 m/sec
Acceleration of the ball [tex]a=4.9m/sec^2[/tex]
We have to find velocity after 4 sec
So ti,e t = 4 sec
According to first equation of motion we know that v = u+at
So [tex]v=1+4.9\times 4=20.6m/sec[/tex]
So velocity of ball after 4 sec will be 20.6 m/sec
