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What is the equation of a line, in point-slope form, that passes through (−2, −6) and has a slope of 1/3 ? y+6=1/3(x+2) y+2=1/3(x+6) y−2=1/3(x−6) y−6=1/3(x−2)

Respuesta :

y + 6 = [tex]\frac{1}{3}[/tex] (x + 2)

The equation of a line in ' point-slope form ' is

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

here m = [tex]\frac{1}{3}[/tex] and (a , b ) = ( - 2, - 6)

y + 6 = [tex]\frac{1}{3}[/tex] (x + 2) → equation in point- slope form


aspena9227

Answer:

y+6=13(x+2)

Step-by-step explanation:

i took a quiz and its correct!!!!

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