Hey there!
[tex] ( \frac{1}{4} ) ^-^2 - (5^0 * 2 ) (1^-^1) \\ \\ 16 - (5^0 * 2) (1^-^1 ) \\ \\ 5^0 = 1 \\ \\ 16 - 1(2) ( 1^-^1 ) \\ \\ 1(2) = 2 \\ \\ 16 - 2(1^-^1) \\ \\ 1^-^1 = 1 \\ \\ 16 - 2(1) \\ \\ 2(1) = 2 \\ \\ 16 - 2 = 14 \\ \\ \\ Answer: 14 [/tex]
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