Respuesta :
[tex]2NO + 2H_{2}[/tex]→ [tex]2H_{2}O+N_{2}[/tex]. For this reaction, rate of reaction is decrease in the concentration of NO with respect to time or decrease in the concentration of H₂ with respect to time or increase in the concentration of H₂O with respect to time or increase in the concentration of N₂ with respect to time.
[tex]-\frac{1}{2} \frac{d[NO]}{dt}= -\frac{1}{2} \frac{d[H_{2} ]}{dt}=+\frac{1}{2} \frac{d[H_{2} O]}{dt}= +\frac{d[N_{2} ]}{dt}[/tex]
Given, [tex]\frac{d[NO]}{dt}=24.0 m/s[/tex]. So, rates of change of [N₂]= [tex]-\frac{1}{2} \frac{d[NO]}{dt}[/tex]=[tex]\frac{1}{2}[/tex]×24.0 m/s=12 m/s. Rate of change of [H₂O] =[tex]+\frac{1}{2} \frac{d[H_{2} O]}{dt}=-\frac{1}{2} \frac{d[NO]}{dt}[/tex]= 24.0 m/s.
