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The daily production of carbon dioxide from an 780.0 mw coal-fired power plant is estimated to be 3.3480 x 104 tons (not metric).a proposal has been made to capture and sequester the co2 at approximately 300 k and 140 atm. at these conditions, the specific volume of co2 is estimated to be 0.0120 m3/kg.what volume of co2 would be collected in a 4.00 year period?

Respuesta :

The production of [tex]CO_{2}[/tex] is [tex]3.3480\times 10^{4} tons/day[/tex]. Converting mass into kg,

1 ton=907.185 kg, thus,

[tex]3.3480\times 10^{4} tons=3.037\times 10^{7} kg[/tex]

Thus, production of [tex]CO_{2}[/tex] will be [tex]3.037\times 10^{7} kg/ day[/tex].

The specific volume of [tex]CO_{2}[/tex] is [tex]0.0120 m^{3}/kg[/tex].

Volume of [tex]CO_{2}[/tex] produced per day can be calculated as:

[tex]V=Specific volume\times mass[/tex]

Putting the values,

[tex]V=0.0120 m^{3}/kg\times 3.037\times 10^{7} kg=364440 m^{3}/day[/tex]

Thus, volume of [tex]CO_{2}[/tex] produced per year will be:

[tex]V=\frac{365 days}{1 year}(364440 m^{3}/day)=1.33\times 10^{8}m^{3}/year[/tex]

Thus, in 4 year volume of [tex]CO_{2}[/tex] produced will be:

[tex]V=1.33\times 10^{8}m^{3}/year\times 4 years=5.32\times 10^{8}m^{3}[/tex]

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