Respuesta :

[tex] \bf \textit{area of a segment of a circle}\\\\
A=\cfrac{r^2}{2}\left( \cfrac{\pi \theta }{180}-sin(\theta ) \right)~~
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\[-0.5em]
\hrulefill\\
r=18.6\\
\theta =123
\end{cases}
\\\\\\
A=\cfrac{18.6^2}{2}\left( \cfrac{\pi (123) }{180}-sin(123^o ) \right)\implies A\approx\cfrac{345.96}{2}\left( \cfrac{41\pi }{60}-0.8386705679 \right)
\\\\\\
A\approx 172.98(1.308084412)\implies A\approx 226.27244158776 [/tex]