Answer:- Empirical formula is MgO.
Solution:- From given information,
Mg = 60.3%
O = 39.7%
Percentages could be considered as their grams and to convert them to moles we divide by their atomic masses.
moles of Mg = [tex]60.3g\frac{1mole}{24.3g}[/tex] = 2.48 mole
moles of O = [tex]39.7g\frac{1mole}{16g}[/tex] = 2.48 moles
We have equal moles of Mg and O, it means the mole ratio is 1:1 and so the empirical formula is MgO.
