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Using this equation 2H2+O2–>2H2O when 47g of water are produced, how many grams of hydrogen must react

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You must react 5.3 g H_2 to produce 47 g H_2O.

Step 1. Calculate the moles of H_2O

Moles of H_2O = 47 g H_2O × (1 mol H_2O/18.02 g H_2O) =2.61 mol H_2O

Step 2. Calculate the moles of H_2

Moles of H_2 = 2.61 mol H_2O × (2mol H_2/2 mol H_2O) = 2.61 mol H_2

Step 3. Calculate the mass of H_2

Mass of H_2 = 2.61 mol H_2 × (2.016 g H_2/1 mol H_2) = 5.3 g H_2

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