Respuesta :
Molarity is defined as number of moles of solute in 1 L of solution.
Here, 0.1025 g of Cu is reacted with 35 mL of HNO_{3} to produced Cu^{2+} ions.
The balanced reaction will be as follows:
Cu+3HNO_{3}\rightarrow Cu(NO_{3})_{2}+NO_{2}+H_{2}O
From the above reaction, 1 mole of Cu produces 1 mole of Cu^{2+}, convert the mass of Cu into number of moles as follows:
n=\frac{m}{M}
molar mass of Cu is 63.55 g/mol thus,
n=\frac{0.1025 g}{63.55 g/mol}=0.0016 mol
Now, total molarity of solution, after addition of water is 200 mL or 0.2 L can be calculated as follows:
M=\frac{n}{V}=\frac{0.0016 mol}{0.2 L}=0.008 mol/L=0.008 M
Thus, molarity of Cu^{2+} is 0.008 M.
Molarity is defined as the number of moles present in the 1 L of solution. The 0.1025 g of Copper (Cu) is reacted with 35 mL of HNO₃ to produce Cu²⁺. The molarity of Cu²⁺ is 0.008 M.
The balanced chemical equation between copper and concentrated nitric acid is:
- Cu + HNO³⁺ [tex]\rightarrow[/tex] Cu(NO₃)₂ + NO₂ + H₂O
From the given equation, stoichiometrically 1 mol of Cu produces 1 mol of Cu²⁺.
Now, we know that:
Mass of copper = 63.55 g/mol
- [tex]\begin{aligned} \text{n}&=\dfrac{\text m}{\text M}\\\\\text{n}&=\dfrac{\text {0.1025 g}}{\text {63.55 g/mol}}\\\\\text{n}&=0.0016 \text{mol}\end{aligned}[/tex]
Now, the molarity of the solution can be calculated as:
- [tex]\begin{aligned}\text {M}&=\dfrac{\text n}{\text V}&=\dfrac{\text {0.0016 mol}}{\text{0.2 L}}& = 0.008 \text M\end[/tex]
Therefore, the molarity of the copper ion is 0.008 M.
To know more about molarity, refer to the following link:
https://brainly.com/question/10733074?referrer=searchResults
