Lateral Area means Area of all four triangles
Now area of 1 triangle = [tex] \frac{\sqrt{3}}{4} a^2 = \frac{\sqrt{3}}{4} 8^2 [/tex]
= [tex] \frac{\sqrt{3}}{4} * 64 = 16\sqrt{3} [/tex] square meters
Now for four triangles we multiply by 4
So
Lateral area of pyramid =[tex] 4* 16\sqrt{3} = 64\sqrt{3} [/tex] m^2
that is Option D
