Answer : The correct answer for rate of consumption of B = [tex] 2.0 \frac{mol}{L*s} [/tex]
Dynamic equilibrium :
Dynamic equilibrium is state of equilibrium where reactants convert to product and product converts to reactant at equal and constant rate . The concentration may not be same but rate will be same .
This occurs when reaction is reversible type .
The hypothetical reaction is :
A ↔ B where ↔ represents reversible reaction
Rate of consumption of A is given as :
[tex] R(a) = k * \frac{d[A]}{dt} [/tex]
Where . R(a) = rate of consumption of A
k = rate constant
[A] = concentration of A
t= time
Rate for consumption of B =
[tex] R (b)= k * \frac{d[B]}{dt} [/tex]
R(b) = rate of consumption of B , [B] is concentration of B
Since the reaction is at dynamic equilibrium , so :
Rate of consumption of A = rate of consumption of B
Given : rate of consumption of A = [tex] 2.0 \frac{mol}{L*s} [/tex]
Hence rate of consumption of B = [tex] 2.0 \frac{mol}{L*s} [/tex]
