Respuesta :

[tex] |\Omega|=5^2=25\\
|A|=1\\\\
P(A)=\dfrac{1}{25}=4\% [/tex]

Answer:

[tex]\frac{1}{25}[/tex]  

Step-by-step explanation:

Given : A spinner has five equal parts labeled from 1 to 5.

           The spinner is spun twice.

To Find: What is the probability of getting a 4 twice in a row?

Solution:

Numbers on spinner = {1,2,3,4,5}=5

Favorable outcome = {4}=1

So, probability of getting 4 on first spin =[tex]\frac{1}{5}[/tex]

Now probability of getting 4 on second spin =[tex]\frac{1}{5}[/tex]

So,  the probability of getting a 4 twice in a row = [tex]\frac{1}{5} \times \frac{1}{25}[/tex]

                                                                               = [tex]\frac{1}{25}[/tex]  

Hence the probability of getting a 4 twice in a row is  [tex]\frac{1}{25}[/tex]