Respuesta :

Moles of carbon in 99.82 g valine

[tex] 99.82 g C_{5}H_{11}NO_{2} [/tex]×[tex] \frac{1 mol C_{5}H_{11}NO_{2}}{117.15 gC_{5}H_{11}NO_{2}} [/tex]×[tex] \frac{5 mol C}{1 mol C_{5}H_{11}NO_{2}} [/tex]

= 4.26 mol C