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N article published in the washington post claims that 45 percent of all americans have brown eyes. a random sample of n=78 college students students found 30 who had brown eyes. consider testingh0:p=.45 ha:p≠.45

Respuesta :

a . The test statistic is -1.160740861

b. The p value is 0.2457473

Let the point estimate be 'a'. The formula for test statistic is:

Z = (a - p) / √ { [ p×(1-p) ]÷n }

Point Estimate 'a' = 30/78 = 0.384615385

Z = (0.384615385 -0.45 ) / √[ (0.45 × 0.55) ] / 78

Z = -0.065384615 / 0.056330071

Z = -1.160740861

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