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How can one fourthx − 3 =one halfx + 8 be set up as a system of equations?

a 4y + 4x = −12
2y + 2x = 16

b 4y − x = −12
2y − x = 16

c 4y + x = −12
2y + x = 16

d 4y − 4x = −12
2y − 2x = 16

Respuesta :

queen6559
The answer is B hope this help u

Answer:

4y − x = −12

2y − x = 16

Step-by-step explanation:

Given : [tex]\frac{1}{4}x-3=\frac{1}{2}x+8[/tex]

We get,

[tex]\frac{1}{4}x-3=y[/tex]   ..........(1)

[tex]\frac{1}{2}x+8=y[/tex] .....(2)

Multiply equation (1) by 4 , we get,

[tex]x-12=4y[/tex]

or [tex]4y-x= -12[/tex]

Now, multiply equation (2) by 2 , we get,

[tex]x+16=2y[/tex]

or [tex]2y-x= 16[/tex]

Hence, option B is correct.

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