we are given
BE=x
ED=x+10
AE=x+1
EC=x+3
we can see that two chords AC and BD are intersecting inside the circle
so, we can use property
[tex] AE*EC=BE*ED [/tex]
now, we can plug values
[tex] (x+1)*(x+3)=(x)*(x+10) [/tex]
now, we can multiply them
[tex] x^2+4x+3=x^2+10x [/tex]
now, we can move all terms on left side
[tex] x^2+4x+3-x^2-10x=0 [/tex]
[tex] 3-6x=0 [/tex]
[tex] x=\frac{1}{2} [/tex]...............Answer
